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Vladimir Sementsov-Ogievskiy authored
The logic around finding overlay here is not obvious. Actually it does two simple things: 1. If new bs is already in backing chain, split from parent bs by several implicit filters we are done, do nothing. 2. Otherwise, don't try to replace implicit filter. Let's rewrite this in more obvious way. Signed-off-by:
Vladimir Sementsov-Ogievskiy <vsementsov@virtuozzo.com>
Message-Id: <20210610120537.196183-6-vsementsov@virtuozzo.com>
Signed-off-by:
Kevin Wolf <kwolf@redhat.com>Vladimir Sementsov-Ogievskiy authoredThe logic around finding overlay here is not obvious. Actually it does two simple things: 1. If new bs is already in backing chain, split from parent bs by several implicit filters we are done, do nothing. 2. Otherwise, don't try to replace implicit filter. Let's rewrite this in more obvious way. Signed-off-by:
Vladimir Sementsov-Ogievskiy <vsementsov@virtuozzo.com>
Message-Id: <20210610120537.196183-6-vsementsov@virtuozzo.com>
Signed-off-by:
Kevin Wolf <kwolf@redhat.com>
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